x^2-20x+49=-2

Solution for x^2-20x+49=-2 equation:

x^2-20x+49=-2

We move all terms to the left:

x^2-20x+49-(-2)=0

We add all the numbers together, and all the variables

x^2-20x+51=0

a = 1; b = -20; c = +51;
Δ = b2-4ac
Δ = -202-4·1·51
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-14}{2*1}=\frac{6}{2}
=3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+14}{2*1}=\frac{34}{2}
=17
$